• mfz@kbin.social
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    1 year ago

    Isn’t the evaluated value different from the expression? i++ returns the value of i before increasing. i-=-1 would return the value after it has been increased. Wouldn’t it be more correct to make it equal to ++i

    • Knusper@feddit.de
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      1 year ago

      In the languages I know, i-=-1 or x=3 are not expressions, but rather statements, so they do not evaluate to a value.

      So, this would be a compiler error:

      a = (x=3)
      
    • maiskanzler@feddit.de
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      1 year ago

      And that’s why post- and pre-increment is non-existant in Python and Rust. It’s an easy source for bugs for a noncritical abbreviation🤷

      • Knusper@feddit.de
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        1 year ago

        They’re especially also a source of bugs, because they encourage manually incrementing indices and manually accessing array positions, which is almost never actually sensible.